References in periodicals archive ?
Since char(R) [not equal to] 2 and by the primeness of R, it follows (1 - e)qe = 0.
By the primeness of R, for any x [member of] J, either d(x)[x.sup.n] = 0 or [d(x), x] = 0.
By the primeness of R, since x [not equal to] 0, [[x.sup.n], y] = 0, in particular [x.sup.n] [member of] Z(R).