# Count

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## Count

On a point & figure chart, an estimation of future price movements. Point & figure charts seek to identify support and resistance levels. Counts are estimates on the likelihood that a security will break through one or the other and result in a large profit or loss.
References in periodicals archive ?
Zdomskyy, "The topological structure of (homogeneous) spaces and groups with countable cs*character," Applied General Topology, vol.
A point x [member of] X is called a point of countable type if there exists a compact subset F with a countable base of open neighborhoods {[U.sub.n]: n [member of] N} in X such that x [member of] F.
A portion of your unreimbursed medical expenses (what you paid out of pocket after medical insurance pays) may reduce your countable income.
It implies that there exists (at most) a countable subset E in [epsilon] such that
* S is said to be strongly left reversible, if there is a family [([S.sub.[gamma]]).sub.[gamma][member of][GAMMA]] of countable left reversible sub-semigroups of S satisfying the conditions 1 and 2 of the previous definition.
In Polish, bagaz 'luggage' and mebel 'furniture' denote discrete entities, consequently, bagaz SG, bagaze PL and mebel SG, meble PL are countable nouns.
As a result [R.sub.[mu]](A) is weakly compact.] Next suppose D [subset or equal to] [bar.[U.sup.w]] with D [subset or equal to] [bar.co]({0} [union] [R.sub.[mu]](D)) and with [bar.[D.sup.w]] = [bar.[C.sup.w]] and C [subset or equal to] D countable. Then since [R.sub.[mu]](D) [subset or equal to] co({0} [union] H{D)) and {0} [union] co({0} [union] H(D)) = co({0} [union] H(D)) we have
Because of the differences in (uniform or less uniform) conceptualization we cannot predict whether the noun denoting a particular entity is countable or not.
That's because a SPIA owned by and payable to the healthy stay-at-home community spouse will generally not be considered a "countable asset" for purposes of qualifying the institutionalized spouse for Medicaid.
If V has the countable basis [{[[upsilon].sub.i]}.sub.i[member of]N] as in [SS13], then there are no non-trivial [S.sub.[infinity]]-invariants in its tensor powers [V.sup.[cross product]k] since every element in these vector spaces is a finite linear combination of the basis elements.
Let G = {0,1,2, ...} be a countable state space and {[X.sub.t], t [member of] T} a collection of G-valued random variables defined on the probability space ([OMEGA], F, P).

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